Posted by Subhotosh Khan on September 30, 2002 at 16:07:56:
In Reply to: Re: Mr B, can you please show me the steps..(n/t) posted by Denis Borris on September 30, 2002 at 15:37:53:
: originally:
: {1/[s^(-1)]}+{1/[t^(-1)]}/[{s^(-1)}{t^(-1)}]=
:
: 1 / s^(-1) + 1 / t^(-1) divided by s^(-1) * t^(-1)
: s + t divided by (1/s)(1/t)
= s + t multiplied by (st)
... Now in the absence of a parenthesis, the multiplication must done first
= s + s*t^2
: that definitely equals st(s + t)
: by: Denis A Borris, EPI (Expert Brackets Interpreter)!!