Posted by Subhotosh Khan on September 29, 2002 at 16:48:35:
In Reply to: Re: calculus! help! posted by Denis Borris on September 29, 2002 at 16:21:37:
: I'll do this one (hope I'm correct!)
: : Find the derivative if Y= (3x^5-7x+5)(x^3+x-a)
Y= (3x^5-7x+5)(x^3+x-a)
Y' = (15x^4-7)(x^3+x-a)+ (3x^5-7x+5)(3x^2+ 1)
and I'll leave it at that ....