Re: calculus! help!


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Posted by Denis Borris on September 29, 2002 at 16:21:37:

In Reply to: calculus! help! posted by M.shugarts on September 29, 2002 at 16:04:21:

I'll do this one (hope I'm correct!)

: Find the derivative if Y= (3x^5-7x+5)(x^3+x-a)

3x^8 + 3x^6 - 3ax^5 - 7x^4 + 5x^3 - 7x^2 + 7ax + 5x - 5a

24x^7 + 24x^5 - 15ax^4 - 28x^3 + 15x^2 - 14x + 7a + 5

...phew!


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