Posted by Joel on September 22, 2002 at 20:21:29:
In Reply to: Same types of probs as Jalomy posted by Faith Richards on September 22, 2002 at 19:56:46:
: I have the same types of probs as Jalomy can any one help me solve for x
: (3*x+25/(x+7))-5= 3/x
: (2*x-1/x)+1= 4/(x+1)
: 4/x - 3/(x+1)=7
Let's take the first one as an example:
To clean it up, multiply both sides by the lowest common denominator, which in this case is x*(x+7):
x*(x+7)*[(3*x+25/(x+7))-5] = (3/x)*x*(x+7)
Now multiply that out and CAREFULLY combine like terms & you should end up with something much more manageable. Give it a try.
The same technique works for the other ones.
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