Posted by Subhotosh Khan on September 22, 2002 at 18:56:10:
In Reply to: Pre-calc...help posted by Jalomy King on September 22, 2002 at 18:43:46:
: I'm still having a little troublewith these!!!!
: Solve for x
: (7x/x-2)+(2x/x+2)=9
:
: (1/x-1)+(x/x+2)=2
:
: (2/x^2-1)+(1/x+1)=5
: Thank you so much
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I'll show you the way to one problem (with assumed correction)
7*x/(x-2)+2*x/(x+2)=9
7*x*(x+2)+2*x*(x-2)=9*{(x+2)*(x-2)} ...[multiply by LCM]
7*x^2+14x+2*x^2-4x = 9*{x^2 -4}
Now you can finish it...
If you need help on the others ...rpost with proper parentheses.