Posted by colin on September 18, 2002 at 10:45:57:
In Reply to: Re: solve polynomial for x? posted by Denis Borris on September 18, 2002 at 02:40:22:
: (6+x)^3/(4+x)^2 = 27
: (6+x)^3 = 27(4+x)^2
: x^3 - 9x^2 -108x -216 = 0
: x(x^2 - 9x -108) = 216
: ...that's as far as I can go;
: the only integer solution is x = -3.
how did you get x = -3 from that?