Posted by Denis Borris on September 18, 2002 at 02:40:22:
In Reply to: solve polynomial for x? posted by Colin on September 18, 2002 at 02:09:32:
: (4/27)*[(6+x)^3/(4+x)^2] - 4 = 0
Well, I forget how to "finish up" this kind, but here's a start:
(6+x)^3/(4+x)^2 = 27
(6+x)^3 = 27(4+x)^2
x^3 - 9x^2 -108x -216 = 0
x(x^2 - 9x -108) = 216
...that's as far as I can go;
the only integer solution is x = -3.