keep after 'em, Joel....I'm learning too! I automatically get nervous every time I see the "sigma summation formula" !


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Posted by Denis Borris on September 12, 2002 at 10:59:23:

In Reply to: Very confusing... posted by Joel on September 12, 2002 at 09:57:08:

: : : : : Is a Sum statement properly termed a "function"
: : : : : so that EITHER of the following:

: : : : : f(n) = n(n+1)/2
: : : : : and
: : : : : f(n) = Sum[from n=1 to n]n

: : : : : BY ITSELF would be correctly considered a function that defines the series {1,3,6,10,15...} ?

: : : : : The former, of course, is a quadratic function. What is the latter? Is it a propositional function?

: : : : You wrote the latter

: : : : f(n) = Sum[from n=1 to n]n

: : : : wrong

: : : : It should be

: : : : f(n) = Sum[from j=1 to n]j

: : : : Then f(n)= n(n+1)/2

: : : : Yes f(n)=n(n+1)/2 defines the series

: : : : {1,3,6,10,15...}

: : : :

: : : Hmmm... now that you pointed it out I agree that
: : : f(n) = Sum[from n=1 to n]n
: : : seems to have too many n's.

: : : But I don't think your f(n) = Sum[from j=1 to n]j looks right either.

: : :
: : : Shouldn't it be:
: : : f(j) = Sum[from j=1 to n]j ?

: So, is this a more general (and correct) way to express this type of relationship:

: f(n) = Sum[from j=1 to n](f(j))
: and in the specific case we were discussing, f(j) happened to be simply j?




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