Re: word sums/Pre algebra class

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Posted by Steve P. on September 12, 2002 at 03:36:19:

In Reply to: Re: word sums/Pre algebra class posted by Denis Borris on September 11, 2002 at 18:58:52:

: : I am having trouble with thi problem.
: : In word sums,each letter stands for a single didgit number. find the numbers that fit the sum to this problem. Hint: there is more than one answer.
: : FOUR
: : + FOUR
: : --------------
: : EIGHT

: Damn it, Stephen...since when are these "algebra"?!
: Anyhow:
: you can tell that F > 4, right?
: you can tell that 2R = T or T+10, right? ***
: Maybe the purpose is to find out IF "you can tell" a few of them "musts"...

: Well there's 32 solutions:
: low : 5238 + 5238 = 10476 : R=8; 2R=16; T=6; so 2R=t+10 ***
: high:9352 + 9352 = 18704 : R=2; 2R=4; T=4; so 2R = T ***

Thanks for your help Denis.

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: : : I am having trouble with thi problem. : : : In word sums,each letter stands for a single didgit number. find the numbers that fit the sum to this problem. Hint: there is more than one answer. : : : FOUR : : : + FOUR : : : -------------- : : : EIGHT : : Damn it, Stephen...since when are these "algebra"?! : : Anyhow: : : you can tell that F > 4, right? : : you can tell that 2R = T or T+10, right? *** : : Maybe the purpose is to find out IF "you can tell" a few of them "musts"... : : Well there's 32 solutions: : : low : 5238 + 5238 = 10476 : R=8; 2R=16; T=6; so 2R=t+10 *** : : high:9352 + 9352 = 18704 : R=2; 2R=4; T=4; so 2R = T *** : Thanks for your help Denis.

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