Added by Wesley Rose on May 31, 2000 at 08:33:51:
A = [(710/113)-(252050/76614)]x{R}^2
A = area of the solid of revolution where R = radius of the arc(s) forming the perimeter of the
Reuleaux triangle or the length of the side(s) of the inscribed equilateral triangle.
[13-({12}^0.5x(355/113))]
O = ------------------------- x {R}
[16-(1420/113)]
O = centroid of the solid of revolution where R =
radius of the arc(s) forming the perimeter of the
Reuleaux triangle or the length of the side(s) of the inscribed triangle.