Re: Damm Derivatives Again!!


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Posted by mr jo on November 13, 2002 at 12:17:30:

In Reply to: Re: Damm Derivatives Again!! posted by Jack on November 11, 2002 at 14:50:42:

How about logaritmically!
you get:
ln(y)=4*ln(x+1)+ 2*ln(x+2)

y'/y=4/(x+1)+2/(x+2)

y'=(x+1)^4(x+2)^2(4/(x+1)+2/(x+2)) Which of course simplifies to the answer below!

: : Hey can anyone tell me how to find the derivative of the function

: : y=(x-1)^4(x+2)^2

: : using differential rules and not by expansion.

: : Thank u....
: : Derek

:
: :Use y`= f`g+fg`
: :f=(x-1)^4 f`=4(x-1)^3
: :g=(x+2)^2 g`=2(x+2)

: : y`=4(x-1)^3(x+2)^2 + 2(x-1)^4(x+2)

: : The solution makes use of the product rule and the chain rule.




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