Posted by Jack on November 12, 2002 at 21:24:09:
In Reply to: Pre-Cal Help! posted by Jewelz on November 12, 2002 at 20:59:31:
: Given the graph of y=f(x)
: Existing points:
: (1,-2),(2,0),(-2,0)
: sketch y=2f(x) and y=1/2f(x)
: Please show how to get a minimum of three the points for the two graphs that are to be sketched.
: y=2f(x) ... the graph is stretched with respect to the y-axis by a factor of 2. Thus, all the y's are multiplied by 2. The three points are (1,-4),(2,0),(-2,0)
: y=1/2 f(x) ... the graph is compressed with respect to the y-axis by a factor of 1/2. Thus, all the y's are multiplied by 1/2. The three points are (1,-1),(2,0),(-2,0)