Posted by mfrizza on November 06, 2002 at 17:03:59:
does this appear correct?
find the area between the following functions...
y = x^3-x
y = 3x
first find points of intersection...3x=x^3-x ---> 0 = x^3-4x ---> 0 = x(x^2-4) ---> 0 = x(x+2)(x-2) so points of intersection are (0,0) (-2,-6) (2,6)
Then I graph...the areas between the curves are clear...
According to the "Integrals of Symmetric Functions", since both functions are odd, they will net out to zero...which means my net area between the curves is also zero....
A = S f(x) - g(x)
Is this correct?
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