Posted by T.Gracken on October 31, 2002 at 18:12:23:
In Reply to: differential equation/integration posted by cavs on October 31, 2002 at 16:26:16:
: need help with this one. I am at a lose with the whole
: dy/dx= (10x^2)/(sqrt1+x^3)
as written you have dy/dx = (10x2)/(1 + x3)
if this is correct, and (i assume) you want to integrate, you can use "u" substitution. Let u=1+x3.
I have the feeling you mis-typed the denominator. However, the same substitution will still provide an easy answer.
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