Posted by T.Gracken on October 28, 2002 at 07:21:09:
In Reply to: Inequalities (quotients) - due tomorrow!! posted by Amr Diab on October 27, 2002 at 21:33:41:
: I cant seem to solve this question 5x/(x^2-1)^2 how do i get the bottom without exponents so i can find out what equals zero? and whats with the 5x? do i take a common factor?? I appreciate the help!
Post a Followup