Implicit Differentiation


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Posted by Gleaming the Cube on October 22, 2002 at 17:08:14:

Does this look right?

Find the Derivative and simplify.

y = (sin^-1 x)^2

okay...my f(u) = u^2 and u = g(x) = (sin^-1 x)^2

Using power rule combined with chain rule...

= 2(sin^-1)du/dx

= 2(sin^-1)(1/[sqrt (x^2-1)]

= 2(sin^-1)/[sqrt (x^2-1)] as the solution


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