Posted by cavs on October 18, 2002 at 05:20:18:
In Reply to: In addition to plotting - I did suggest "think" posted by Subhotosh Khan on October 11, 2002 at 15:49:51:
: : : : need some help with this one I must do y' and y'' for it
: : : : y = I2x-3I
: : : : theII brackets should be absolute value sign
: : : : thanks
THANKS FOR NO HELP!!!!!!!
: : : *********************************
: : I know what the graph looks like. I do not know how to show my work for it. The first derivative dealing with the absolute value is new to me.
: ******************************
: y = 2x - 3 for x (Greater Than or Equal to).GE 1.5
: y' = 2 for x .GE. 1.5
: y" = 0
: y = -2x + 3 for x .LE 1.5
: y' = -2 for x .LE 1.5
: y" = 0