Posted by T.Gracken on October 16, 2002 at 19:41:38:
In Reply to: Finding the slope of the tangent line posted by Ronnie Dobbs on October 16, 2002 at 15:55:42:
: Find the slope of the tangent line to the curve y = x^3 at the point (-1, -1).
: So we're using...
: lim x-> -1
: [ f(x) - f(a) ] / x - a
: lim x-> -1
: [x^3 - f(-1)] / x - (-1) = [x^3 - (-1)] / x - (-1)
: = lim x->-1 [x^3 + 1] / x + 1
: This is where I'm stuck...can anyone shed some light on what my next step(s) is? Thanks.
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