Posted by flo on October 15, 2002 at 10:57:42:
In Reply to: Re: improper posted by T.Gracken on October 15, 2002 at 10:51:47:
: I think you should check your work. I got an answer of 10/9. I think you are forgetting the limits of integration with respect to polar coordinates. Try to substitute a trig function for x and this problem will work out for you.
: : improper integral of 1/x^2 from 0 to 1
: : Doesn't exist, correct???
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