Re: improper


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Posted by T.Gracken on October 15, 2002 at 10:51:47:

In Reply to: improper posted by flo on October 15, 2002 at 08:46:52:

I think you should check your work. I got an answer of 10/9. I think you are forgetting the limits of integration with respect to polar coordinates. Try to substitute a trig function for x and this problem will work out for you.

: improper integral of 1/x^2 from 0 to 1
: Doesn't exist, correct???





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