Re: limits


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Posted by Subhotosh Khan on October 07, 2002 at 08:29:48:

In Reply to: limits posted by miguel on October 06, 2002 at 22:35:43:

: I can't seem to come up with the right answer for this problem. I'd appreciate any help.

: lim
: X->pi/4 (sinX - cosX)/cos2X
*******************************

(sinX - cosX)/cos2X

=(sinX - cosX)/[(cosX)^2 - (sinX)^2]

=(sinX - cosX)/[ (cosX - sinX)* (cosX + sinX)]

= -1/(cosX + sinX)

Take it from here....




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