Posted by miguel on October 06, 2002 at 22:35:43:
I can't seem to come up with the right answer for this problem. I'd appreciate any help.
limX->pi/4 (sinX - cosX)/cos2X
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Comments: : I can't seem to come up with the right answer for this problem. I'd appreciate any help. : lim : X->pi/4 (sinX - cosX)/cos2X
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