Posted by T.Gracken on October 06, 2002 at 08:30:08:
In Reply to: Absolute functions graphing posted by Brendan Osborne on October 05, 2002 at 21:34:30:
: Ok i have a question. When graphing an absolute function like y=|x^2+4x| how do u find the x intercepts and the vertex. also what about the function
: y= |x^3-1|
to determine the x-intercepts, let y=0 and solve resulting equation (this is one way that never changes regardless of the equation).
so for y = |x2 + 4x|, the x-intercepts will be at x=0 and at x=-4.
for vertex (?), determine x-coordinate of vertex for y = x2 + 4x and then substitute into the value into the original function. you should get (-2, 4).
for y = |x3 - 1|, follow same proceedure for intercepts [you should get one real x-intercept when x=1]. Since this is a cubic there will be no vertex
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