Posted by Brad Paul on September 28, 2002 at 18:35:38:
In Reply to: Precalculus Question posted by Mary on September 28, 2002 at 16:44:29:
: I'm can't figure out how to approach this question"
: Suppose we want to make a poster containing 50 square inches of printed matter surrounded by a 3" border at the top and bottom, and a 2" border along each side. How does the total area of the poster depend on the width of the printed matter?.
: Any clues, anyone? Please?
Let A be the area of the printed matter, and w the width of the
printed matter. If the printed matter is in the shape of a rectangle
we can find the height of the printed matter via h=A/w. Let b be the
3 inch border at the top and bottom and c be the 2 inch width of the
border along each side. Now with these variable lets write an equation
for the total area of the poster. Lets call it Atotal
Atotal=(2 c+w)(2 b+A/w)
Notice this equation is just a height time width equation. The width
is 2 time the border width because there is one on each side and the
the width of the printed matter. The height is 2 times the borders
plus height written in terms of the Area and width of the printed
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