Posted by colin on September 27, 2002 at 11:00:18:
In Reply to: Re: 2nd order linear DE posted by Subhotosh Khan on September 27, 2002 at 08:32:08:
the book's answer is:
e^y = (t + c2)^2 + c1
Any clue how they arrived at that?thx.
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Comments: : the book's answer is: : e^y = (t + c2)^2 + c1 : Any clue how they arrived at that? : thx.
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