Re: really quick help


[ Follow Ups ] [ Post Followup ] [ Calculus Message Board ] [ FAQ ]

Posted by VM on September 23, 2002 at 17:47:40:

In Reply to: really quick help posted by sean on September 23, 2002 at 16:08:58:

: what is the derivative of 1/x² ?
: i keep getting lost in all the x and h garbage. i get to (x²-x²-2hx-h²)/[x²(x²+2hx+h²)] and then i get a bit confused. is that much even right?

1/x^2 can be written as 1x^-2 from there you get -2x^-3. -2x^-3 is the answer or you can write it as -2/x^3.





Follow Ups:



Post a Followup

Name:
E-Mail:

Subject:

Comments:

Optional Link URL:
Link Title:
Optional Image URL:


[ Follow Ups ] [ Post Followup ] [ Calculus Message Board ] [ FAQ ]