2nd order linear DE... need help. (Prob #2)


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Posted by colin on September 23, 2002 at 11:17:22:

I'm also at an impasse on this prob:

yy'' + (y')^2 = 0
let v = y'
dv/dt = y'' = (dv/dy)(dy/dt) = v(dv/dy)
yv(dv/dy) + v^2 = 0
dv/dy = -v/y
dv/v = - dy/y
ln(v) = -ln(y) + c1
v = -y + c1

somehow the book answer is v = c1/y at this point.
I don't see how they got that...




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