Yes I have used that method....


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Posted by Subhotosh Khan on September 13, 2002 at 15:10:57:

In Reply to: Re: Please write your problem correctly.... posted by Soroban on September 13, 2002 at 13:34:07:

That method is simple as long as we do not have repeated roots for the denominators (I suppose that's why chaste-in-heart-mathematicians do not like this method).Suppose you had:

f(n)/[n*(n-a)^2] this has to be "broken up" as

A/n + B/(n-a) + (Cn + D)/(n-a)^2
Now problem gets complicated (for n=a)......




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