integration- finding area under graph

Posted by bana on September 13, 2002 at 07:52:55:

Hi there, I have a problem here with using integration to find the area under the graph because the graph cuts the x axis at x=6. ( i have to find the area where x=0 to x=9)
the function is y=25-x^2
i intergrated to 25x-(1/3)x^3+c
I have find the area of -18. how can i break it up so that i'd get a correct area figure?

Follow Ups:

• Re: integration- finding area under graph Soroban 13:17:03 09/13/02 (0)
• Check your problem again.... Subhotosh Khan 08:20:11 09/13/02 (1)
  • Re: Check your problem again.... bana 00:19:00 09/14/02 (0)

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