That's neat trick ... I had totally forgotten...(n/t)


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Posted by Subhotosh Khan on September 10, 2002 at 08:45:05:

In Reply to: Re: how do u integrate 1/sinx ?? posted by Jack on September 09, 2002 at 19:06:49:

: : what trig function is 1 / sin x

: :
: : : help, how do u integrate 1/sinx

: :try this dx/sinx = sinx dx/sinx^2
: : = sinx dx/(1-cosx^2)

: :now integrate by parts - u=cosx, dv=sinx dx
: :
: :you end up with du/(1-u^2)




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