Posted by colin on September 10, 2002 at 01:13:29:
In Reply to: Re: Sorry... solution equation is wrong! posted by Soroban on September 09, 2002 at 13:16:12:
: The integral becomes: INT 2u du/(g - cu),
: which will require some long division (or some
: trick like "adding zero").
Can you please explain how to do the trick?
: And THAT's why there are two integrals.
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