# thank you

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Posted by T.Gracken on September 04, 2002 at 19:56:01:

In Reply to: Re: integration help posted by Soroban on September 04, 2002 at 18:41:39:

: : How do I integrate this?

: : dx/(a+Sqrt(x))

: : Can someone explain the technique please?
: : I don't need the actual answer, just help with the approach.
: : I can do dx/Sqrt(x) fine (2Sqrt(x)) but this seems to be a beast of another nature...

: First of all, T.Gracken's approach is correct -- and very courageous!

: I assumed he'd already tried Substitution and didn't try it until just now.
: And when I did -- WOW!

: Let sqrt(x) = u
: Then: x = u^2
: And: dx = 2u du

: Substitute: INT 2u/(u+a) du

: Divide: 2 INT [1 - a/(u+a)] du

: There!

Thank you!

I sometimes get tunnel vision and just go with it. For some reason I thought a basic substitution would have already been attempted and did not even consider a simple substitution (and manipulating the fraction by "adding zero to the numerator").

I should be severly whipped for all that extra crap I did.

...I think I've been teaching too many developmental classes of late.

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