Posted by benjii on August 30, 2002 at 09:37:29:
In Reply to: inverse derivative posted by Ryan on August 30, 2002 at 09:05:02:
: x=g(x) is the inverse of y=f(x)
: does d2y/dx2 = 1/(d2x/dy2)?
: sugg: g' is a function of x and x is a function of y
: find the derivative of y'=1/x' with respect to x, and use the chain rule on the right side.
: I make U=x' and du = x", so i get x"(-1/x'^2)
: --> The answer is y"=-x"/(x'^3) --> but I am only getting y"=-x"/(x'^2)
: What am I missing????