inverse derivative


[ Follow Ups ] [ Post Followup ] [ Calculus Message Board ] [ FAQ ]

Posted by Ryan on August 30, 2002 at 09:05:02:

x=g(x) is the inverse of y=f(x)
does d2y/dx2 = 1/(d2x/dy2)?

sugg: g' is a function of x and x is a function of y
find the derivative of y'=1/x' with respect to x, and use the chain rule on the right side.

I make U=x' and du = x", so i get x"(-1/x'^2)

--> The answer is y"=-x"/(x'^3) --> but I am only getting y"=-x"/(x'^2)

What am I missing????



Follow Ups:



Post a Followup

Name:
E-Mail:

Subject:

Comments:

Optional Link URL:
Link Title:
Optional Image URL:


[ Follow Ups ] [ Post Followup ] [ Calculus Message Board ] [ FAQ ]