Posted by Dartchen on August 29, 2002 at 12:00:30:
Was given a problem that originally seemed simple but I think I'm making some conceptual errors on.
integral tan(x^1/2)dx
My original thoughts on the solution would be substitution
x^1/2 = u
du = 1/2x dx
2 integral (sin(u)/cos(u))du
cos(u) = t
dt = -sin(u)du
sooo... -2integral dt/t = -2ln|t|+C
-2ln|cos(u)|+C
-2ln|cos(x^1/2)|+C ??
I'm probably way off but any hints/help would be GREATLY appreciated!!
Thanks!!