Posted by Subhotosh Khan on August 27, 2002 at 12:09:47:
In Reply to: Re: minimising posted by Soroban on August 27, 2002 at 02:18:04:
: :But how does it prove that the equation
: : y=(2000+20x+10x^1/2)/x cannot be minimised (i.e. the function does not have a convex). I thought we have to take the second derivative because for a convex to occur f"(x)>0.
: Please listen carefully, KK.
: The function had NO critical values.
: (We set the first derivative equal to 0
: and could not solve for x.)
: Therefore, there are NO maximums or minimums.
: Why do we take the second derivative?
: To test the Critical Values for max or min.
: But there are NO critical values to test.
: [Your flashlight doesn't work. I tell you that
: there are no batteries in it. And you insist on
: trying a battery-tester?]
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