Re: minimising

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Posted by KK on August 25, 2002 at 18:57:24:

In Reply to: Re: minimising posted by Soroban on August 25, 2002 at 02:54:25:

How about this one? y=(2000+20x+10x^1/2)/x
I got y'=(-2000x^-2) - (5x^-3/2)
Why is it a square root can't have negative? How come this one does not have a minimum?

Follow Ups:

Re: minimising T.Gracken 13:08:10 08/26/02 (0)
Re: minimising Soroban 12:38:16 08/26/02 (8)
- sorry Mr.S. your post didn't show up until after I posted -nt- T.Gracken 13:09:56 08/26/02 (7)
  - Re: minimising kk 20:22:05 08/26/02 (6)
    - Re: minimising Soroban 02:18:04 08/27/02 (5)
      - Flashlight -- I like that analogy... (n/t) Subhotosh Khan 12:09:47 08/27/02 (4)
        
        Re: minimising and maximising KK 01:52:43 08/28/02 (2)
        
        What's your function - [y=(2000+20x+10x^1/2)/x ] or [y=(2000+20x+10x^1/2)] Subhotosh Khan 16:00:01 08/28/02 (0)
        
        Look at Mr.G's post at the top of the thread... Subhotosh Khan 08:31:58 08/28/02 (0)
        
        Re: minimising and maximising KK 01:52:42 08/28/02 (0)

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