Posted by Subhotosh Khan on August 13, 2002 at 08:21:36:
In Reply to: Re: y=3^x posted by bana on August 12, 2002 at 18:35:25:
: y=In(u)
: dy/dx = (1/u) * du/dx
: Yea,that's the bit i don't understand.
: y=In3
: dy/dx=1/In3*1/3?=? ***********************
No!!!!
When you say
y = ln 3 .... you are defining y to be constant or
y = 1.098612...
When you differentiate y in this case - you are differentiating a constant. The answer should then be.....
ZERO
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