Posted by bana on August 12, 2002 at 18:35:25:
In Reply to: Re: y=3^x posted by Joel on August 12, 2002 at 17:13:27:
y=In(u)dy/dx = (1/u) * du/dx
Yea,that's the bit i don't understand.y=In3dy/dx=1/In3*1/3?=?
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Comments: : y=In(u) : dy/dx = (1/u) * du/dx : Yea,that's the bit i don't understand. : y=In3 : dy/dx=1/In3*1/3?=?
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