Posted by T.Gracken on August 08, 2002 at 14:46:40:
In Reply to: exponential function posted by karen on August 08, 2002 at 13:39:00:
: why can't I get this problem?!?
: solve the following exponential function - no calculator:
: e^(2x) - 3e^(x) + 2 = 0
: A) ln 3, 0
: B) 0, ln 2
: C) -ln 2, 0
: D) -ln 3, 0
: E) ln 2, ln 3
: thanks to anyone who can help
Try this (for a start)
note: e^(2x) - 3e^(x) + 2 = (ex - 1)(ex - 2)
so rewrite equation as
(ex - 1)(ex - 2) = 0
and use the zero product rule (a.k.a. zero factor theorem, et.al.)