Posted by Don on August 02, 2002 at 18:23:09:
: To show that the summation of k^k / k! diverges my book gives this as an example:
: a sub(k+1)/a sub(k) =(k+1)^k+1 / (k+1)! * k!/ k^k
: =(k+1/ k)^k
: = (1 + 1/k)^k = e as k goes to infinity.
: What I don't see is how they factored (k+1)!, cancel out terms and got from
: (k+1)^k+1 / (k+1)! * k!/ k^k
: to
: (1 + 1/k)^k .
: When I tried I got a different answer.
: Can someone help me?
: Thanks!