Single Displacement Lab

Purpose: What happens to an iron nail when placed in copper sulfate?

Materials:
beaker or glass jar
iron nail
copper (II) sulfate solution
paper towel
ruler
Caution: Copper (II) sulfate solution is poisonous.  Handle it with care and wash your hands thoroughly after lab.

Procedure:

  1. Obtain copper (II) sulfate solution from your teacher.
  2. Add 3-4 cm copper (II) sulfate solution to the jar, use ruler to measure.
  3. Observe nail and solution.
  4. Place nail in solution.  Leave in for 5-10 minutes.  Remove the nail and place it on the paper towel.
  5. Observe the nail and solution.
Observations/ Data:
Observation Nail Color Solution Color
Before Reaction Silver-grey Blue
After Reaction Dark red White-blue
Fe+CuSO4                > FeSO4+Cu

Review:

Help me out here!
1.  What are the reactants in this reaction?
a. Copper sulfate and iron b. Iron sulfate and copper c. Copper oxide and iron
2.  What are the products in this reaction?
a. Iron sulfate and copper b. Iron oxide and Copper c. Copper sulfate and iron
3.  What element caused the CuSO4 solution to change color?
a. Copper b. Iron c. Iron Oxide
4.  What element caused the nail to change color?
a. Iron b. Copper c. Copper sulfate
5.  What type of chemical reaction is this? How do you know?
a. Double displacement b. Decomposition reaction c. Single displacement
6.  What happened to the nail when it was placed in the solution?
a. The iron and copper sulfate underwent a single displacement reaction and became copper and iron sulfate, causing the iron of the nail to replace the copper in the solution.  b. The iron sulfate reacted with the copper to create coppper sulfate and iron, which coated the nail with copper sulfate turning the nail dark red while turning the solution white. c. It changed color
 
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