Addition , Subtraction , Division

At times even simple addition takes a lot of time as the numbers are big and complicated

. Here is an alternative method which helps you in adding even big numbers quite fast .

For example , suppose you have to add the following :

345 + 378 = ?

Let us bifurcate the numbers into two parts . 345 can be bifurcated as 34 and 5 . Similarly , 378 can be bifurcated into 37 and 8 as shown above. I have used the slash [/]mark as bifurcation symbol.

Now we have two separate parts for addition : 34+37 and 5+8. After separate addition, they have been written as below:

34/5+37/8 = 71/13

Now how to get the final result ?

On the right-hand side , you have two digits but there shoud be onlyone digit because after bifurcating the numbers , you have kept only one digit on the right.[Detailed explanation is given in our course Magical Methods and its Application in data Interpretation].

In this particular example, on the right-hand side

We have 13 but we should have only one digit as we have deduced. So what should we do?

Add the left most digit of RHS to the left hand side, i.e. carry over 1 from 13 and add to 71. Your answer is:

71/13 = 72/3 = 723

You can follow the same principle of addition with four digit numbers.

2345+346 = ?

Bifurcation can be done as follows:

23/45+3/46 OR 234/5+34/6

The only thing you have to keep in mind is that the number of digits taken on the right side of the bifurcation should be same for both the numbers and also in the answer.

If you are getting more than two digits, then

you should adjust the number of digits accordingly.

Subtraction

The principle you have applied above can be utilized for subtraction also. In this case, the process will be slightly different. Have you ever wondered how easy it is to add or subtract numbers ending with zero? Why so?

Because you work with less number of digits. This is the principle we apply in our subtraction problems. Suppose you have to solve the following problem:

2345-348=?

If you will do it using the conventional method, it will take time. Try the following:

The above problem can be bifurcated as shown as below:

2345-345-3=?

2000-3=1997

By using the bifurcation method, this complicated problem became simpler and could even be solved mentally. Now let us consider another example:

3245-308=?

The above problem can be bifurcated as shown below:

32/45-3/08=?

Let us now work with these bifurcations, ie

32-3=29 and 45-8=37

32/45-3/08=29/37=2937

Your answer is 2937.

You can make up your own methods of bifurcation. There can be many such methods. It is very difficult to force a change on anybody. But you must adopt a promising technique.

Division

I have classified division into two main types from the examination point of view. One, where the dividend is large and the divisor is small. ie:

3786/128=?

And another, where the dividend is small and the divisor is large. ie:

86/129=?

In the example where the dividend is large and divisor is small, you can obtain the approximate answer as given.

Remove the last digit from the dividend and the divisor. The above example:

3786/128=?

Can be written as

379/13=

Divide it and you will get an approximate answer. This has given you 29.2 as the approximate answer.

379/13=29.2

Now let us try to find out the exact answer:

3786/128=29.58

The difference between the exact answer and the approximate answer is not much and you can very well use this principle.