Triangles

Area:

1/2 x B x H

Perimeter:

S1 + S2 + S3

Elliptical Area:

3.14 x B x H

B: Base (Horizontal Leg)

S: Side

B: Base (Horizontal Leg)

H: Height (Vertical Leg)

H: Height (Vertical Leg)

Examples

Area

First, we have to multiply 0.5 or 1/2 by

the Base (Horizontal Leg).

The Horizontal Leg is 6, 6 x 0.5 is 3.

We then need to multiply the height

(vertical leg) by 4. 3 x 4 is 12. The area

of the triangle on the left is 12 sq. units.

Perimeter

First, we have to add 6 with 8, we get

14. Then we have to add 14 to 10,

we get 24. Therefore, the perimeter

of the triangle on the left is 24 units.

Elliptical Area

We have to multiply 3.14 (pi) by 2.

We get 6.28. Then we need to multiply

that by 3. 6.28 x 3 is 18.84.

The elliptical area of the triangle on

the left is 18.84 sq. units.

The Pythagorean Theorem

Solve for the Hypotenuse

Solve for the Leg

A2 + B2 = C2

C2 - B2 = A2

A & B: Legs

A & B: Legs

C: Hypotenuse

C: Hypotenuse

Examples

Solve for the Hypotenuse

First, we have to square 3 and 4.

The square of 3 is 9, the square of 4 is

16. 16 + 9 is 25. The square root of 25

is 5. The hypotenuse of this triangle

has a length of 5 units.

Solve for the Missing Leg

First, we have to square 6 and 10.

The square of 6 is 36. The square of 10

is 100. 100 - 36 is 64. The square root of

64 is 8. Therefore, the horizontal leg of

this triangle has a length of 8 units.